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Array-3 > seriesUp
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| Given n>=0, create an array with the pattern {1, 1, 2, 1, 2, 3, ... 1, 2, 3 .. n} (spaces added to show the grouping). Note that the length of the array will be 1 + 2 + 3 ... + n, which is known to sum to exactly n*(n + 1)/2.
seriesUp(3) → {1, 1, 2, 1, 2, 3} seriesUp(4) → {1, 1, 2, 1, 2, 3, 1, 2, 3, 4} seriesUp(2) → {1, 1, 2} ...Save, Compile, Run See Also: Example Code Java help: If Boolean Logic | Strings | While and For Loops | Arrays and Loops |
Forget It! -- delete my code for this problem 321.0
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