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Logic-2 > closeFar
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| Given three ints, A B C, return true if one of B or C is "close" (differing from A by at most 1), while the other is "far" (differing from both other values by 2 or more). Note: Math.abs(int) computes absolute values.
closeFar(1, 2, 10) → true closeFar(1, 2, 3) → false closeFar(4, 1, 3) → true ...Save, Compile, Run See Also: Example Code Java help: If Boolean Logic | Strings | While and For Loops | Arrays and Loops |
Forget It! -- delete my code for this problem 215.0
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