String-2 > starOut
prev  |  next  |  chance

Return a version of the given string, where for every star (*) in the string the star and the chars immediately to its left and right are gone. So "ab*cd" yields "ad" and "ab**cd" also yields "ad". starOut("ab*cd") → "ad" starOut("ab**cd") → "ad" starOut("sm*eilly") → "silly" ...Save, Compile, Run public String starOut(String str) { } See Also: Example Code Java help: If Boolean Logic | Strings | While and For Loops | Arrays and Loops prev  |  next  |  chance   |  JavaBat  >  String-2

Forget It! -- delete my code for this problem 254.0

Copyright Nick Parlante 2006-09 - privacy