Recursion-1 > array220
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Given an array of ints, compute recursively if the array contains somewhere a value followed in the array by that value times 10. We'll use the convention of considering only the part of the array that begins at the given index. In this way, a recursive call can pass index+1 to move down the array. The initial call will pass in index as 0. array220({1, 2, 20}, 0) → true array220({3, 30}, 0) → true array220({3}, 0) → false ...Save, Compile, Run public boolean array220(int[] nums, int index) { } See Also: Example Code Java help: If Boolean Logic | Strings | While and For Loops | Arrays and Loops prev  |  next  |  chance   |  JavaBat  >  Recursion-1

Forget It! -- delete my code for this problem 351.0

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