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String-3 > sumDigits
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| Given a string, return the sum of the digits 0-9 that appear in the string, ignoring all other characters. Return 0 if there are no digits in the string. (Note: Character.isDigit(char) tests if a char is one of the chars '0', '1', .. '9'. Integer.parseInt(string) converts a string to an int.)
sumDigits("aa1bc2d3") → 6 sumDigits("aa11b33") → 8 sumDigits("Chocolate") → 0 ...Save, Compile, Run See Also: Example Code Java help: If Boolean Logic | Strings | While and For Loops | Arrays and Loops |
Forget It! -- delete my code for this problem 318.0
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